Problem 2: numerical integration

In this problem, you are supposed to estimate the integral of arccosh(x) from x=0 to 2. No credit will be given for the numerical answer. According to Maple:
>evalf(int(arccosh(x), x=1..2);

.901864986

Instead, you are to use the following data for partitioning the interval into three: x0 = 1, x1 = 1 1/3, x2 = 1 2/3, x3 = 2:

x arcsinh(x) arccosh(x)

1 .88 0
1 1/6 .99 .57
1 1/3 1.10 .80
1 1/2 1.19 .96
1 2/3 1.28 1.10
1 5/6 1.37 1.21
2 1.44 1.32

> trap := (0 + 1.32 + 2*(.80+1.10))/6;

> mid := (.57+.96+ 1.21)/3;

> simp := trap/3 + 2*mid/3;

>