D[x Cos[xy],x] D[xCos[x*y],x] D[x Cos[x y],x] D[x Cos(x y),x]
Out[1]=
Cos[xy]
General::spell1:
Possible spelling error: new symbol name "xCos"
is similar to existing symbol "Cos".
Out[1]=
y xCos'[x y]
Out[2]=
Cos[x y] - x y Sin[x y]
Syntax::bktwrn:
Warning: "Cos(x y)" should probably be "Cos[x y]".
Out[2]=
2 Cos x y
Only the third one of these is right.
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